Charles’s Law – States of Matter – Chemistry Class 11

Charles’s Law – States of Matter – Chemistry Class 11


Do subscribe to Ekeeda Channel and press bell icon to get updates about latest engineering HSC and IIT JEE main and advanced videos Hello Friends in the last lecture we have did a numerical based on Boyle’s law as well as we have also did a theory which is based on boyles law and now we are going to do the next law that is charles law so let us long about so friends as only are seeing this is a law which is based on Charles law it states that it says that a constant pressure the volume of a given mass of a gas increases or decreases so it says that if a given mass of a gas has a particular volume and in that case suppose the pressure is kept to be constant so the pressure so the volume can be increased or can be decreased by by 1 divided by print 273 point one five of its volume at 0 degree Celsius for every degree a rise or fall in the temperature it states that whenever a constant pressure if a given mass of the gas is been kept having a particular volume and if we increase the temperature or if we decrease the temperature then this will affect the volume of the yes so in simple words I could say that that if if I increase the temperature from that is from 0 degree Celsius to a particular temperature then that will create a rise in the volume by one by two seventy three point one five and if I decrease the temperature then this will be giving a fall if one in the volume that is that is also by 1 divided by 273 point one five so therefore it depends on the volume so therefore the volume and the temperature are both dependent on each other when the temperature is when when the pressure is being kept constant in simple words I could say that according to Charles law it states that at constant pressure the volume of the given mass of the gas is daily proportional to its absolute temperature it means the volume is slightly proportional to temperature and that also at constant yes at constant pressure so therefore the volume will increase the temperature will increase and if the temperature will decrease then the volume of the that particularly gas will decrease so therefore this explain is that the volume is directly proportional to the temperature so this was the second statement and which was very much easy to understand but let us understand that how the first statement is very much valid to obey it just slow and how does it has made a statement for transform so let us learn about then suppose let v-0 be the volume of the given mass of the gas at zero degree senses so this is the temperature that I have kept I have kept zero degree senses as the temperature and the volume which is present of the gas which is present at the senses is said to be V naught so the temperature is increased by 80 degree Celsius suppose if I increase the temperature from zero senses to T degree Celsius at constant pressure and this all should be at constant pressure so then the two the strands flow the increase in the volume will be as the first statement said that if we increase or if we decrease the temperature then the monuments change so the one will change from where the money will change from V is U multiplied by that is Delta V that is the change in volume that is from V 0 into e divided by 273 point 1 5 so this P is nothing but the T degree Celsius that we have mentioned here itself so if I increase the temperature then this would be the change would explains on the original volume that is V naught and if I decrease again this would be the change but the change will be in negative proportion so now what I could say is that the final volume that is V T will be V T that is the total time or total volume or the final volume which is equals to V naught the initial volume which was at 0 degree Celsius plus Delta V that is the change in volume after the increase in the volume when I have increased the temperature that is from 0 degree census to a degree Celsius so this is what I have kept so what I could do is I could solve this also again so for that since we have the value of Delta V so I will substitute the value here and let us see what is the answer we could get or how can we explain this charge so now as far as you know that is V T is equal to 2 that is total volume which is equals to V naught that is initial volume plus the change in volume that is dense than P so in this case what we have got it as we have got the Delta V value as V naught into E divided by 273 0.15 so this is what we have got so I could arrange this equation in a very simple form so this would be written as this can be written as V naught or V 0 which is I take V 0 as the common in this case so in that case what I would get is 1 plus T divided by 273 point 1 5 so this is what we have one so I could arrange this thing so this would lead let us to make this s 273 point 1 5 plus T the whole divided by 273 point 1 5 so this is the value that we have got for the final temperature or the depth the volume if he increase the temperature from 0 degree Celsius to 2 T distances so this is what we have put but in this case as we know that 273 point but 5 is nothing but 0 degree Celsius itself so therefore I know that suppose at 0 degree Celsius because what is Shane to be 0 degree Celsius means it is a temperature at which the volume is V naught so therefore I could take the 0 degree Celsius as T naught itself but it is in 0 degree senses so I can convert into Kelvin so therefore basically if I have to convert into Kelvin then this will be 0 degree Celsius plus 273 point 1 5 which is nothing but two seventy three point one five so this is the value of T note that our world but suppose if I increase the temperature from 0 degrees access to T degree senses then means what I am talking about so suppose if I increase the temperature that is from that is from 0 D senses to teen or TDD senses then in this case what I could say is that suppose the degree senses is something which I’m increasing from 0 degree senses so what will happen is this T degree Celsius plus 273 0.15 will actually be the TV senses or I could say it as the temperature that is for e so in this case what I could say it is the value that we have got or I could keep it as capital T because this is some where we could get confused so I will keep it as capital T so in this case if we look at the former let me update earlier that definition so in this case what I could see is a two seventy three point one five plus T is nothing can be replaceable by this steam why the two seventy three point one five can be replaced by T naught so I could write the overall equation as VT which is equals to V naught into instead of T degree senses plus 273 point one five I could write it as T the volt divided by two seventy three point one five which is nothing but t naught so I could arrange this thing as VD divided by T which is equals to V naught divided by T so this is something which clearly indicates that the volume is done if proportional to the temperature so in this case as I say this would be the T naught one yes I have forgotten so this is the thing that we could clearly mention that the volume is being diagonal to the temperature at constant pressure so this was based on child saw so this is the first condition when this is the other for example even I could pick like this also that is V 1 / suppose if V 1 is a tiny proportion to T 1 so what I could write it as I could write it as V 1 is equals to K that is a proportionality constant into even so I could write this thing as V 1 divided by T 1 is goes to K similarly suppose if I take another condition like V 2 which is entirely dependent on T 2 so therefore V 2 is equals to K that is proportionately constant into T 2 then 4 again the value of V 2 divided by T 2 will be somewhere equals to K so this implies that suppose if both are having the same way because suppose they proportionally constant have the same way that is V 1 divided by T 1 as well as V 2 divided by T 2 so therefore P code clearly indicate or become clearly say that the formula could be written as according to Charles law that is V 1 divided by T 1 is equals to V 2 divided by T 2 so this is the formula this is what the Chancellor was indicating so thank you friends for watching this video I hope you have liked this video and you have understood this ones are very clearly along with the definition and along with the explanation that we have did right now so yes share this video with your friends nes don’t forget to subscribe you – thank you so much

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3 thoughts on “Charles’s Law – States of Matter – Chemistry Class 11

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